How many moles of sodium nitrate nano3 would be produced from the complete reaction of 253 g sodium chromate na2cro4

= 3.12 moles of NaNO3

The equation for the reaction is;

Pb(NO3)2+Na2CrO4 → PbCrO4+2NaNO3

Molar ratios in the reaction are ; 1 : 1 : 1 : 2

Which means; One mole of (Na2CrO4) produces two moles of (NaNO3)

We can calculate the number of moles of Na2CrO4,

Moles (na2CrO4) = 253g /162

                             = 1.56 moles

Moles of NaNO3 will be;

 = 1.56 moles x 2 = 3.12 moles

Therefore, the moles of NaNO3 that will be produced will be 3.12 moles