How many moles of kl are contained in 100.0ml of a .20m solution?

0.020 mol  

Step-by-step explanation:

Data:

V = 100.0mL

c = 0.20 mol·L⁻¹

Calculations:

Molarity = moles/litres  

c = n/V

Multiply each side by V:     n = cV

(a) Convert millilitres to litres

100.0 mL × (1 L/1000 mL) = 0.1000 L

(b) Calculate the moles

n = 0.1000 L × (0.20 mol/1 L) = 0.020 mol

The solution contains 0.020 mol of KI.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.