The reaction of sulfuric acid (h2so4) with potassium hydroxide (koh) is described by the equation below. suppose 0.05 l of koh with unknown concentration is placed in a flask with bromthymol blue indicator. a solution of 0.10 m h2so4 is dripped into the koh solution. after exactly 0.033 l of h2so4 is added, the indicator changes from blue to yellow. what is the concentration of the koh.

h2so4+> k2so4+2h2o

chem eqn is H2SO4+2KOH--->K2SO4+2H2O

1x H2SO4 reacts with 2x KOH

0.033L of 0.10M H2SO4 has 0.033 x 0.10 = 0.0033 moles

2x 0.0033 = 0.0066 moles of KOH

conc of KOH = moles/vol = 0.0066/0.05

=0.132M

im not exactly sure but i think its b!

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.