How many molecules of ethane ( c2h6) are present in 0.197g of c2h6?

3.945 x 10²¹ molecules

Explanation:

Firstly, we need to calculate the no. of moles using the relation:n = mass/molar mass = (0.197 g)/(30.07 g/mol) = 6.55 x 10⁻³ mol.It is known that every 1.0 mol of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³).∴ 0.197 g of C₂H₆ will contain = (6.55 x 10⁻³ mol)(6.022 x 10²³) = 3.945 x 10²¹ molecules.

I’m pretty sure it’s false i’m not sure

A.