In glycolysis, fructose 1,6-bisphosphate is converted to two products with a standard free-energy change (delta g'°) of 23.8 kj/mol. under what conditions encountered in a normal cell will the free-energy change (delta g) be negative, enabling the reaction to proceed spontaneously to the right?

Answer;

When there is a high concentration of fructose-1,6-bisphosphate relative to the concentration of products.

Explanation;Fructose-1,6-bisphosphate is formed at the first irreversible reaction unique to glycolytic pathway, the commited step, after the phosphorylation of fructose 6-phosphate. The reaction is catalyzed by the enzyme phosphofructokinase, and it is the primary control site in glycolysis. When there is a high concentration of fructose-1,6-bisphosphate relative to the concentration of products, the change in the free-energy will be negative, and this enables the reaction to proceed towards the formation of products from fructose-1,6-bisphosphate.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !