Chemistry, 04.02.2020 10:50 taten9551

Charles’ law can be expressed mathematically as v=kt. if the constant k for 6.0 l of gas is 0.020 l/k (liters per kelvin), what is the temperature of the gas?

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Charles’ law can be expressed mathematically as v=kt. if the constant k for 6.0 l of gas is 0.020 l/...

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