Agas at 155 kpa and standard temperature has an initial volume of 1.00 l. the pressure of the gas rises to 500 kpa as the temperature also rises to 135°c. what is the new volume?

2.16 l
0.463 l
0.207 l
4.82 l

In the combined gas equation, (P1V1)/T1=(P2V2)T2, where P1 is the initial pressure, V1 the initial volume, T1 the initial temperature,P2 is the final pressure, V2 the final  volume, T2 the final  temperature,

substituting for the values: (155kPa× 1.00L)/273K=(500kPA× V2)/408K

V2=(155kPa×1.00L×408K)/(273K×500kPa)

    = 0.463L

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.  

wher is the rest of the question