Balance this equation co2(g) + h2o (g) show that the balanced equation obeys the law if conversation of mass

CO₂ + H₂O ⟶ H₂CO₃

Explanation:

1. Complete the unbalanced equation

CO₂ + H₂O ⟶ H₂CO₃

2. Put a 1 in front of the most complicated-looking formula (H₂CO₃):

CO₂ + H₂O ⟶ 1H₂CO₃

3. Balance all atoms other than H and O

Balance C

We have fixed 1 C on the right. We need 1 C on the left. Put a 1 in front of CO₂.

1CO₂ + H₂O ⟶ 1H₂CO₃

4. Balance O:

We have fixed 3 O on the right. We need 3 O on the left. We have fixed 2 O in the CO₂.  We must fix one ore O on the left. Put a 1 in front of H₂O.

1CO₂ + 1H₂O ⟶ 1H₂CO₃

Every formula now has a coefficient. The equation should be balanced.

Atom  On the left  On the right

  C               1                     1

  H               2                    2

  O               3                    3

The balanced equation is

CO₂ + H₂O ⟶ H₂CO₃

There are the same numbers of each type of atom on each side of the equation, so the Law of Conservation of Mass is obeyed.

the answer for sodium is 0.186

the answer for rubidium is 0.251