(this question is from apex in course: physical science sem 2 which of the following are double-displacement reactions? check all that apply. a. hc2h3o2(aq) + nahco3(aq) → nac2h3o2(aq) + h2co3(aq) b. naoh(aq) + hci(aq) → naci(aq) + hoh(i) c. zn (s) + hci (aq) → znci2 (aq) + h2 (g) d. 2cu (s) + o2 (g) → 2cuo (s)

The following double-displacement reactions are fully applied/answered:

A. HC2H3O2(aq) + NaHCO3(aq) → NaC2H3O2(aq) + H2CO3(aq)

B. NaOH(aq) + HCI(aq) → NaCI(aq) + HOH(I)

(The answers are A. & B.)

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.