How many moles of sulfuric acid (h2so4) are needed to react completely with 6.8 moles of lithium hydroxide (lioh)? 2lioh + h2so4 → li2so4 + 2h2o

The correct answer is 3.4 moles of sulfuric acid (H₂SO₄) are needed to react completely with 6.8 moles of lithium hydroxide.  

2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O

The given chemical equation is balanced.  

By using stoichiometry, one can witness the following:  

2 moles of LiOH requires 1 mole of H₂SO₄

So, 6.8 moles of LiOH requires (1/2) × 6.8 = 3.4 moles of H₂SO₄

2.3 mol H2SO4

Explanation:

I just took the test ;)