What is the molarity of a solution prepared from 100g of alf3 dissolved in 1200 ml of water?

Given value is

Solute=100g of AlF3

Solution= 1200ml

Formula is;

Molarity = mole of solution/ solution in liter

We have to find moles first.

For this purpose apply formula

No.of mole=mass in g/ molar mass

Mass= 100g

Molar mass = 83.9767g/mol

No of mole = 100/83.9767

= 1.191mol

Now convert solution into liter

1200ml= 1200/1000= 1.2L

Now put these values in molarity formula

Molarity= no.of mole/ solution in liter

= 1.191mole of AlF3/1.2L of water

= 0.9925M of AlF3