Refer to the balanced equation. ( quick) 8h2s+8cl2→s8+16hcl how many l of chlorine gas, at stp, were required if 2.28 mol reacted? a) 6.38 x 10^0 l cl2 b) 1.02 x 10^–1 l cl2 c) 5.12 x 10^1 l cl2 d) 4.09x 10^2 l cl2

C) L

Explanation:

According to Avogadro's law, 1 mole of every gas occupies 22.4 Liters at STP.

Thus from the balanced chemical equation, 8 moles of hydrogen sulfide reacts with 8 moles of chlorine gas.

i.e 8 moles of hydrogen sulfide reacts with of chlorine gas.

2.28  moles of hydrogen sulfide reacts with of chlorine gas.