2kclo3 → 2kcl + 3o2 how many moles of oxygen are produced by the decomposition of 6.0 moles of potassium chlorate, kclo3? question 7 options: 2.0 moles 3.0 moles 6.0 moles 9.0 moles

From the balanced equation  3 moles of oxygen are produced from 2 molecules of potassium chlorate.

So the number of moles of oxygen from 1 mole of chlorate = 3/2 = 1.5.

By proportion  the number of moles produced from 6 moles of  the chlorate =

= 6 * 1.5  = 9 moles  (answer).

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