For the equation 2no + o2 → 2no2, how many liters of nitrogen dioxide would be formed from 56 liters of nitrogen monoxide at stp? (assume you have plenty of oxygen)

49.30 L

Explanation:

1. Write the chemical equation.

Ratio:    2 L                 2 L

           2NO +O₂ ⟶ 2NO₂

V/L:       56

2. Calculate the volume of NO₂.

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

According to the law, 2 L of NO₂ are formed from 2 L of NO.

Then, the conversion factor is (2 L NO₂/2 L NO).

Volume of NO₂ = 56 × 2/2

Volume of NO₂ = 56 L

answer: cellular respiration takes in food and uses it to create atp, a chemical which the cell uses for energy. usually, this process uses oxygen, and is called aerobic respiration. it has four stages known as glycolysis, link reaction, the krebs cycle, and the electron transport chain.