Answer the following for the reaction: 3agno3(aq)+na3po4(aq)→ag3po4(s)+3na no3(aq) 1. how many milliliters of a 0.255 magno3 solution are required to react with 31.1 ml of 0.135 mna3po4 solution? 2. how many grams of silver phosphate are produced from the reaction of 23.0 ml of a 0.195 magno3 solution and excess na3po4?

1) Volume of required is 55.98 mL.

2) 0.62577 grams of is produced.

Explanation:

1) Molarity of

Volume of

Molarity of

Volume of

According to reaction, 1 mole of reacts with 3 mole of , then, 0.0041985 moles of will react with:

moles of that is 0.0125955 moles.

Volume of required is 55.98 mL.

2)

Number of moles of

According to reaction, 3 moles of gives 1 mole of , then 0.004485 moles of will give: moles of that is 0.001495 moles.

Mass of =

Moles of × Molar Mass of

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of is produced.