The equation below shows the decomposition of lead nitrate. how many grams of oxygen are produced when 11.5g no2 is formed? 2pb(no3)2(s) -> 2pbo(s) + 4no2(g) + o2(g)

2 g

Explanation:

As can be seen from the balanced chemical equation, 2 moles of lead nitrate produce 4 moles of nitrogen dioxide.

of lead nitrate produces of nitrogen dioxide.

184 g of nitrogen dioxide will be produced by 662.4 g of lead nitrate

So 11.5 g of nitrogen dioxide will be produced by= of lead nitrate

As can be seen from the balanced chemical equation, 2 moles of lead nitrate produce 1 mole of oxygen.

of lead nitrate produces 32 g of oxygen.

41.4 g of lead nitrate produces = of oxygen.

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