Gastric acid ph can range from 1 to 4, and most of the acid is hcl. for a sample of stomach acid that is 3.03x10^-2 m in hcl, how many moles of hcl are in 10.9 ml of the stomach acid?

Given the molarity of the solution is.

The volume of the solution is 10.9/1000 L

Number of moles of HCl = Molarity * volume of the solution in L

Number of moles of HCl =*

Number of moles of HCl = 2.7 moles.

Therefore number of moles of HCl in 10.9 ml of the stomach acid is 2.7 moles

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