2nh3 + 2 o2 → n2o + 3 h2o if 80.0 grams of o2 are reacted in the above reaction, how many grams of n2o will be produced (mm o2=32 g/mol; nh3=17.04 g. mol, n2o=44.02 g/mol, h2o=18.02 g/mol)? 29.1 g 67.6 g 55.0 g 165 g

   2 NH3 + 2 O2 → N2O + 3 H2O

mass of O2 = 80.0g

moles of O2 = 80.0/32 = 2.5 moles O2

moles of N2O = 2.5 moles O2 x   1 mole N2O      = 1.25 moles N2O

                                                       2 moles of O2

mass of N2O produced ;

moles = mass/Molar mass

mass = moles x Molar mass

        = 1.25 x 44.02

        = 55.025 g N2O

55.025g of N2O is produced in this reaction.