Agalvanic cell has the overall reaction: zn(s) 2eu(no3)3(aq)  zn(no3)2(aq) 2eu(no3)2(aq) which is the half reaction occurring at the anode

The half reaction occurring at anode is

Explanation:

In a chemical cell, substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

For the given chemical cell reaction:

Oxidation half reaction (anode):  

Reduction half reaction (cathode):      ( × 2 )

Here, zinc is loosing electrons and is getting oxidized and europium is gaining electrons and loosing electrons.

Hence, the half reaction occurring at anode is

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :