Show work and inlcude units on each number sulfuric acid reacts with sodium hydroxide. if 3.50 mol h2so4 is made to react with 10.0 mol naoh, identify the limiting reagent. first write the balanced equation, then do the calculations. show all work!

 The  limiting  reagent  is   H₂SO₄

   calculation

Step 1 :write the equation for reaction

2 NaOH + H₂SO₄  → Na₂SO₄   + 2 H₂O

Step  2: use the mole ratio to determine the  moles of product  produced from each reactant

that is   from  equation above,

NaOH : Na₂SO₄  is 2 :1 therefore the  moles of Na₂So₄

= 10.0 moles x 1/2 =  5.0 moles

H₂SO₄ :Na₂SO₄  is 1:1 therefore the moles  of Na₂SO₄  is also = 3.50 moles

H₂SO₄  is the limiting reagent since  it produces  less amount of Na₂SO₄

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

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