What is the [oh-] in a solution with a poh of 11.25

 The [Oh-]  in the  solution  with a POh of 11.25  is 5.623 x 10^-12 M

  calculation

POH= - log [ OH-]

Therefore  - log [oH-]  =11.25

 To calculate [oh-]  concentration find the antilog  of 11.35

 =  10^- 11.25  =  5.623  x 10^-12 M

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.