Cobalt has the chemical symbol co and the atomic number 27. how many protons, neutrons, and electrons would be found in an atom of cobalt-58? 31 protons, 31 neutrons, 27 electrons 31 protons, 27 neutrons, 31 electrons 27 protons, 31 neutrons, 27 electrons 27 protons, 27 neutrons, 31 electrons

The answer is 27 Protons, 27 Electrons, and 31 Neutrons. Hope this helps!

27 protons, 31 neutrons, 27 electrons

Explanation:

Atomic number is equal to the number of protons and equal to the number of electrons.  

So 27 = number of protons = Number of electrons.  

Mass number is the sum of the number of proton and neutrons

Mass number = 58  = Number of proton + Number of  neutrons

Number of neutrons = Mass number - Number of protons = 58 - 27 = 31

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

i believe the answer is three water molecules