In the reaction, 522.49 moles of barium chloride and unlimited amount of sulfuric acid react, to give, as products barium sulfate and hydrochloric acid. how much is the minimum amount of reactant required of sulfuric acid in moles. then additionally, how much product is produced of barium sulfate, in grams, and hydrochloric acid in grams?

1) Answer is: the minimum amount of reactant required of sulfuric acid is 522.49 moles.

Balanced chemical reaction:

BaCl₂(aq) + H₂SO₄(aq) → BaSO₄(s) + 2HCl(aq).

n(BaCl₂) = 522.49 mol; amount of barium chloride.

From chemical reaction: n(BaCl₂) : n(H₂SO₄) = 1 : 1.

n(H₂SO₄) = n(BaCl₂).

n(H₂SO₄) = 522.49 mol; amount of sulfuric acid.

2) Answer is: mass of  barium sulfate is 121949.16 grams.

From chemical reaction: n(BaCl₂) : n(BaSO₄) = 1 : 1.

n(BaSO₄) = n(BaCl₂).

n(BaSO₄) = 522.49 mol; amount of barium sulfate.

m(BaSO₄) = n(BaSO₄) · M(BaSO₄).

m(BaSO₄) = 522.49 mol · 233.4 g/mol.

m(BaSO₄) = 121949.16 g; mass of barium sulfate.

3) Answer is: mass of hydrochloric acid is 38089.52 grams.

From chemical reaction: n(BaCl₂) : n(HCl) = 1 : 2.

n(HCl) = 2 · n(BaCl₂).

n(HCl) = 2 · 522.49 mol.

n(HCl) = 1044.98 mol; amount of hydrochloric acid.

m(HCl) = n(HCl) · M(HCl).

m(HCl) = 1044.98 mol · 36.45 g/mol.

m(HCl) = 38089.52 g; mass of hydrochloric acid.

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.

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