F38.7 grams of lithium chlorate decomposes, how many grams of oxygen gas can be produced? 2liclo3 ? 2licl + 3o2 41.1 g o2 20.6 o2 9.13 g o2 6.85 g o2

 The grams    of oxygen gas  that can be produced    is 20.6  grams of O₂

calculation

2LiClO₃ →  2 LiCl + 3 O₂

step 1:  find the moles of LiClO₃

moles = mass÷ molar mass

from periodic table the molar mass of LiClO₃ =6.9 +35.5  +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281  moles

step 2:  use the  mole ratio  to calculate the moles of O2

from equation above, LiClO₃:O₂  is 2:3  

therefore the moles of  O₂=0.4281 moles x3/2 =0.6422  moles

Step 3: find mass  of O₂

mass= moles x molar mass

from periodic table the  molar mass of  O₂ = 16 x2= 32 g/mol

mass=0.6422  moles  x  32 g/mol = 20.6 grams of O₂

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