Given the following reaction: 3feo + 2cu3n --> fe3n2 + 3cu2o how many moles of copper (i) nitride are needed to form 35.7 grams of copper (i) oxide? question options: .213 .166 .198 .312

(Answer) 0.166 moles of copper (I) nitride are needed.

Mass of copper (I) oxide = 35.7 g

Moles of copper (I) oxide formed by the reaction = (Mass / molar mass)

= ( 35.7 g / 143.09 g/mol ) = 0.25 moles

According to the balanced chemical equation,

mole ratio of copper (I) nitride and copper (I) oxide = 2: 3

Therefore, moles of copper (I) nitride needed to form 0.25 moles of copper (I) oxide = (2/3 x 0.25) moles = 0.166 moles.

Thus, 0.166 moles of copper (I) nitride are needed to form 0.25 moles of copper (I) oxide.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

c. 75.7

i think that is the right