0.303 g of a compound with the formula mcl2 reacts with aqueous agno3 to yield 0.783 g of a white precipitate of solid agcl according to the equation below. what is the identity of m?

Given:

Mass of the compound MCl2 = 0.303 g

Mass of AgCl formed = 0.783 g

To determine:

The identity of M

Explanation:

Chemical reaction-

MCl2   +   2AgNO3  →   2AgCl  +   M(NO3)2

0.303 g                          0.783 g

Based on the reaction stoichiometry: 1 mole of MCl2 forms  2 moles of AgCl

Molar mass of AgCl = 143 g/mol

# moles of AgCl formed = 0.783/143 = 0.00547 moles

Therefore moles of MCl2 reacted = 0.00547/2 = 0.00274 moles

Molar mass of MCl2 = 0.303/0.00274 = 110.58 g/mol

Atomic mass of M = 110.58 - 2(35.5) = 40.58 g/mol

The element with atomic mass 40 g/mol is calcium Ca

Ans: Identity of M = Ca. The molecule is CaCl2

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.

b. examine and describe cells