If the symbol x represents a central atom, y represents outer atoms, and z represents lone pairs on the central atom, the structure a central x atom has two lone pairs. two y atoms are attached to x with single bonds. could be abbreviated as xy2z2. classify these structures by the hybridization of the central atom.

Given information:

Central atom = X

# lone pairs on X = 2

# bonds by X = 2 i.e 2 X-Y bonds.

The structure can be represented as Y-:X:-Y

It can be abbreviated as XY2Z2 where Z2 represents the two lone pairs on the central atom X.

Based on the electron geometry which accounts for the 2 two pairs and the 2 bonds, the central atom X would be sp3 hybridized with a tetrahedral geometry

From a molecular geometry perspective (which does not consider the lone pairs), the structure would be linear.

i believe the answer is c. "baking" is the gerund, while "baking blueberry muffins" would be the gerund phrase. hope this ! : )

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.