Chemistry, 01.07.2019 03:00 smartperraorwhateva

Calculate the rms speed of an oxygen gas molecule, o2, at 35.0 ∘c .express your answer numerically in meters per second.

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Answer from: Tanija1995

The μ rms speed = 489.9661 m / s

Further explanation

Gas particles move randomly (both speed and direction, as vector)

Average velocities of gases can be expressed as root-mean-square velocity. (V rms)

$\large {\boxed {\bold {\mu_ {rms} = \sqrt {\frac {3RT} {M_m}}}}$

R = gas constant, 8.314 J / mol K

T = temperature,

Mm = molar mass of the gas particles

μ rms = root mean square velocity of Gas Particles.

From this equation shows that the velocity of the gas is inversely proportional to the molar mass of the gas particles

μ ≅ 1 / mm

So that the greater the molar mass of the gas particles, the smaller the speed (the slowest)

Oxygen gas molecule, O₂ has a molar mass: 0.032 kg / mol

T = 35 C + 35 + 273 = 308 K

then :

$\rm \mu_{rms}=\sqrt{\dfrac{3\times 8.314\times 308}{0.032} }\\\\\mu_{rms}=489.9661\frac{m}{s}$

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