What is the molarity of potassium ions in a 0.122 m k2cro4 solution

 The molarity   of potassium  ions  in a 0.122 M  K2CrO4  is 0.244 M

Explanation

write dissociation reaction  for K2CrO4

that  K2CrO4 (aq)→ 2K^+ (aq)  + CrO4^2- (aq)

K2CrO4  dissociate to give  2  ions of potassium ,therefore  the molarity  of potassium ion = 2 x 0.122  = 0.244 M

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

the answer would be a