How many moles of potassium chloride and oxygen can be produced from 100.0g of potassium chlorate? the balanced equation is: 2 kclo3=2kcl+3o2

Answer : The moles of potassium chloride and oxygen produced can be 0.813 and 2.44 respectively.

Explanation : Given,

Mass of = 100.0 g

Molar mass of = 123 g/mole

The balanced chemical reaction will be,

First we have to calculate the moles of .

Now we have to calculate the moles of and .

From the balanced chemical reaction we conclude that,

As, 2 mole of react to give 2 mole of

So, 0.813 mole of react to give 0.813 mole of

and,

As, 2 mole of react to give 3 mole of

So, 0.813 mole of react to give 3 × 0.813 = 2.44 mole of

Therefore, the moles of potassium chloride and oxygen produced can be 0.813 and 2.44 respectively.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml