You discover a chemical reaction that produces 1 moles of valuable propane for every 6 moles of carbon supplied. essentially, this is an exchange rate of 1 moles of propane for every 6 moles of carbon. if you have 1.8 moles of carbon, how many moles of propane can you produce using this reaction?

Here we have to calculate the number of moles of valuable propane can be prepared from 1.8 moles of carbon.

From 1.8 moles of carbon 0.3 moles of propane can be prepared by the reaction.

From 6 moles of carbon (C) 1 moles of valuable propane (C₃H₈) can be prepared.

Thus from 1.8 moles of C we can obtain ×1.8 = 0.3 moles  of the propane can be prepared.

Thus the amount of propane produced in this reaction is determined.

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