If you mix 25.0 ml of 0.10 m hcl with 0.055g of calcium carbonate, how many moles of hcl are not neutralized by the calcium carbonate

The chemical equation representing the reaction of calcium carbonate with hydrochoric acid is:

Moles of HCl given =

Moles of =

Moles of HCl that would react with :

=0.0011mol HCl

Moles of HCl that would not be neutralized = 0.0025 mol - 0.0011 mol

                                                                        = 0.0014 mol HCl

i think it is true since you can test the answer and can use observations to complete it.

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.