Using a skeletal structure, give the structure corresponding to the name (s)−3−iodo−2−methylnonane.

Explanation:

For the given compound: (s)-3-iodo-2-methylnonane, only third carbon- atom (marked with red dot) is the chiral atom (as it is attached to 4 different substituents), so the configuration will be assigned to this C-atom only.

In assigning the configuration of this compound, the priorities are assigned based on their atomic masses. The lowest priority group ( that is Hydrogen) should lie on the vertical line. But here, it is lying on the horizontal line, so the configuration will be reversed.

The configuration coming out when H is on the horizontal line is R, but the actual configuration will be S.

The structure of the given organic compound is shown in the image attached.

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1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%