The reaction for the burning of one type of match tip is as follows: p4s3(s) + 8 o2(g) p4o10(g) + 3 so2(g) what volume of so2 at stp can be produced by burning 1.00 g p4s3 in excess o2?

a] work out mass of 1 mole P4S3 -- call this Y grams

b] eqtn tells you 1 mole P4S3 gives 3 moles SO2 [= 3 x 22.4L at STP]  

c] by simple proportion  

1g P4S3 gives (3 x 22.4)/Y SO2 at STP answer

the increase of protons   hope this