7.00g of ech reactant is available, determine the theoretical yield of 2hg(l) + o2(g) - 2 hgo

7.88 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.  

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

Step 1. Gather all the information in one place with molar masses above the formulas and masses below them.  

:     200.59   32.00   216.59

              2Hg +    O₂ ⟶ 2HgO

Mass/g: 7.00    7.00  

Step 2. Calculate the moles of each reactant

Step 3. Identify the limiting reactant  

Calculate the moles of HgO we can obtain from each reactant.  

From Hg:

From O₂:  

The limiting reactant is Hg because it gives the smaller amount of HgO.

Step 4. Calculate the mass of HgO that you can obtain from Hg.

because natural gas is colorless, odorless, and tasteless, distributors add mercaptan (a chemical that smells like sulfur) to give natural gas a distinct unpleasant odor (it smells like rotten eggs). they locate the types of rock that are likely to contain natural gas deposits.