Chemistry, 04.07.2019 08:00 JacobWat

Compound a, c10h22o, undergoes reaction with dilute h2so4 at 50°c to yield a mixture of two alkenes, b and c, c10h20. the major alkene product, b, gives only 3-pentanone after ozone treatment followed by reduction with zinc in acetic acid. draw the structure of the major alkene product, compound b.

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Answer from: lizreed2002

Answer :

When compound A, undergoes reaction with dilute H_2SO_4 at 50^oC to yield a mixture of two alkenes, B and C. In these two alkenes B is the major product and C is the minor product.

According to the saytzeff's rule, the more substituted alkene is formed as a major product during dehydration that means double bond is formed due to loss of water molecule. Dilute H_2SO_4 is act as a dehydrating agent.

Now the major product alkene B gives only 3-pentanone after ozonolysis followed by reduction with zinc in acetic acid.

The reaction is shown below.

Compound a, c10h22o, undergoes reaction with dilute h2so4 at 50°c to yield a mixture of two alkenes,

Answer from: Quest

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Answer from: Quest

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

$\delta h=e_p-e_r$

$\delta h$ = enthaply

$e_p$ = energy of products

$e_r$ = energy of reactants

as $e_p< e_r$ , thus $\delta h$ comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.

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Compound a, c10h22o, undergoes reaction with dilute h2so4 at 50°c to yield a mixture of two alkenes,...

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