Consider the reaction 2 al + fe2o3 to 2fe + al2o3. if 60.0g of al is reacted with excess fe2o3, determine the amount (in moles) and mass (in grams) of al2o3 produced

 The  amount  of  Al2O3  in moles=  1.11 moles    while in  grams   = 113.22 grams

    calculation

     2 Al  + Fe2O3 → 2Fe  + Al2O3

    step  1: find the moles of Al  by  use of moles= mass/molar  mass  formula

    =  60.0/27= 2.22  moles

    Step 2: use the mole ratio to determine the  moles of Al2O3.

 The  mole ratio  of Al : Al2O3 is  2: 1 therefore the moles of Al2O3= 2.22/2=1.11  moles

Step 3:    finds the mass  of  Al2O3  by us of  mass= moles x molar mass formula.

The molar  mass of Al2O3  =  (2x27)  +( 16 x3) = 102  g/mol

mass is therefore=  102  g/mol  x 1.11= 113.22 grams

c. 75.7

i think that is the right