Given that you added about 5ug of purified acid phosphatase to tube a, calculate the amount of acid phosphatase that was present in 400ul of the wheat germ extract in the tube b.

Hey there!:

Amount of purified acid phosphatase added to tube A = 5 ug ( micrograms )

Amount of acid phosphatase present in 400 ug of wheat germ extract  in tube B :

1 / 100 = 5x / 400 =

100 x = ( 0.5 ) ( 400 ) =

x = (0.5 ) ( 400 ) = 100

x = 200 / 100

x =  2 ug

The amount of acid phosphatase present in 400 ug of the  wheat germ in tube B is 2 ug

Hope that helps!

the answer is   c.) 1575 j.

explanation: