2suppose that a new element (e) were discovered that existed as three natural isotopes: 25% of atoms had a mass of 278, 38% had a mass of 281, and the remained had a mass of 285. what would be listed as the atomic mass of this element? explain your logic and show all steps.

Atomic mass of the element E is 281.73 amu.

Explanation: We are given an element E, having 3 isotopes.

Atomic mass of the element is calculated by:

.....(1)

Fractional abundance can be calculated by:

Mass of isotope 1 = 278 amu

Fractional abundance of isotope 1 = =0.25

Mass of isotope 2 = 281 amu

Fractional abundance of isotope 2 = 0.38

Mass of isotope 3 = 285 amu

Total fractional abundance = 1

Fractional abundance of isotope 3 = 1 - (0.25+0.38) = 0.37

Putting all the values in equation 1, we get

Atomic mass of the element E = 281.73 amu.

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.