How many moles of mgcl2 are there in 308

Answer is: there are 3.23 moles of magnesium chloride (MgCl₂).

m(MgCl₂) = 308 g; the mass of the magnesium chloride.

M(MgCl₂) = 95.21 g/mol; molar mass of the magnesium chloride.

n(MgCl₂) = m(MgCl₂) ÷ M(MgCl₂).

n(MgCl₂) = 308 g ÷ 95.21 g/mol.

n(MgCl₂) = 3.23 mol; the amount of the magnesium chloride.

The answer is 3.23 mol.

Given data:

Mass in gram of MgCl2 = 308

Molecular mass = 95.21 g/mol

Number of moles = ?

Formula:

Number of moles = Mass in grams / Molecular mass

By putting the values in above formula:

Number of moles = 308 / 95.21

                           = 3.23 mol

So if the weight of MgCl2 is 308 grams. So by the formula of number of moles, it will contain 3.23 moles. Mass in grams of MgCl2 is divided by its molecular mass to get number of moles of MgCl2.

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