The ph of 0.10 m solution of an acid is 6. what is the acid dissociation constant of the acid? 10-11 10-12 10-5 10-6

Dissociation constant of the acid is .

Explanation: Assuming the acid to be monoprotic, the reaction follows:

pH of the solution = 6

and we know that

As HA ionizes into its ions in 1 : 1 ratio, hence

As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:

Dissociation Constant of acid, is given as:

Putting values of in the above equation, we get

Rounding it of to one significant figure, we get