Agoldsmith melts 12.4 grams of gold to make a ring. the temperature of the gold rises from 26°c to 1064°c, and then the gold melts completely. if gold’s specific heat is 0.1291 joules/gram degree celsius and its heat of fusion is 63.5 joules/gram, how much energy is gained by the gold? the gold gains a total of joules of energy. i was given this by somebody. no idea what to do with this. qj=(12.4g*(1064-26)°c*0.1291j/g/°c) +(12.4g*63.5j)

The gold gains a total of 2.468 kilo-joules of energy.

Explanation:

Total heat or energy gained by the gold is equal to heat applied and heat required to melt the gold completely.

Total energy = Q+ Q'

Heat of fusion of gold =

Mass of gold melted ,m= 12.5 g

Specific heat of gold ,c= 0.1291 joules/gram °C

Change in temperature = ΔT = 1064°C - 26°C = 1038 °C

Heat of applied to the gold = Q

Total energy = Q+ Q'

= 2,468.82 Joule= 2.468 kilo-Joule

The gold gains a total of 2.468 kilo-joules of energy.

am i too late?

explanation:

the answer is option a.