Amixture consists of glucose and water. what is the percent composition of glucose in the mixture if it contains 1.3 moles of glucose (c6h12o6) and the total mass of the mixture is 276 grams? a. 17.7% b. 26% c. 35% d. 77% e. 85%

The  percent composition of glucose  in the  mixture  is 85 %  ( answer E)

        Explanation

percent  composition of glucose = (mass of glucose /  mass  of the mixture) x 100

Step 1:  calculate the mass  of glucose ( C6H12O6)

mass of glucose =  moles of glucose  x  molar mass  of glucose

molar  mass of C6H12O6  = [( 12 x6) + ( 1  x12) + ( 16 x6)= 180 g/mol

mass  is therefore= 1.3 moles x 180g/mol = 234  grams

Step 2: calculate  the percent composition

= mass of glucose /mass of mixture x 100

= 234 g/276 g  x 100  = 85 %(answer E)

The percent composition of glucose in the mixture is 85%

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