Chemistry, 08.07.2019 20:00 christophercordero15

Is li2o(s)+so2(g)→li2so3(s) a redox reaction

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Answer from: therealpr1metime45

No. The reaction is not a redox reaction.

Redox reaction is defined as a chemical reaction in which both oxidation and reduction of chemical species takes place. In such reactions, one of the chemical species undergoes reduction and other undergoes oxidation.

Here, oxidation means increase in oxidation state and reduction means decrease in the oxidation state.

The given reaction is as follows:

$Li_{2}O(s)+SO_{2}(g)\rightarrow Li_{2}SO_{3}(s)$

Here, the most stable oxidation state of oxygen is -2. Calculate the oxidation state of Li and S before and after the reaction completion.

On reactant side:

Let the oxidation state of Li in $Li_{2}O$ be x thus,

2x+(-2)=0

Or,

2x=2

Or,

x=+1

Similarly let the oxidation state of S in $SO_{2}$ be y thus,

y+2(-2)=0

Or,

y-4=0

Or,

y=+4

Thus, oxidation state of Li and S on reactant side is +1 and +4 respectively.

Now, the product formed is $Li_{2}SO_{3}(s)$ , it is an ionic compound thus it contains $Li^{+}$ and $SO_{3}^{2-}$ ions.

Thus, the oxidation state of Li will be +1.

Calculate the oxidation state of S in $SO_{3}^{2-}$ .

Let the oxidation state be z thus,

z+3(-2)=-2

Or,

z=-2+6=+4

The oxidation state of Li and S on the product side is also +1 and +4 respectively.

Since, the oxidation state of any of the chemical species is not changed (no oxidation or reduction take place), the reaction is not a redox reaction.

Answer from: Quest

Wind will blow from one direction to another.

Answer from: Quest

$\frac{239}{94}pu+\frac{1}{0}n ====> \frac{y}{z}x+\frac{134}{54}xe+3\frac{1}{0}$

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137 subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54 subtract 54 from both sides.

40 = z

answer

$\frac{103}{40}x=\frac{103}{40}zr$

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