How could you make 300ml of a solution at a concentration of 10g nacl per 100 ml?

You would dissolve 30 g NaCl in enough water to make 300 mL solution.

Mass of NaCl = 300 mL solution × (10 g NaCl/100 mL solution) = 30 g NaCl.

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

20 drops hope this