2.   use your periodic table to determine the number of protons, electrons and neutrons that are in the following elements:                                               a. bromine (br)    protons, electrons, neutronsb. aluminum (al)  protons, electrons, neutronsc. beryllium (be)      protons, electrons, neutrons

Protons are the positively charged particles, electrons are the negatively charged particle and neutrons are neutral particles.

The number of protons is same as the atomic number of element.

The number of electrons is equal to the number of protons as atom consists of same number of protons and electrons.

The number of neutrons is equal to subtraction of number of protons from mass number.

That is, Mass number - Number of protons = Number of neutrons.

a. Bromine ()

atomic number of bromine is 35. Thus, number of protons = 35

And, number of electrons  = 35

Number of neutrons  = Mass number - Number of protons

Mass number of bromine  = 79.9

Therefore, Number of neutrons  = which is approximately equal to 45.

b. Aluminum ()

atomic number of aluminium is 13. Thus, number of protons = 13

And, number of electrons  = 13

Number of neutrons  = Mass number - Number of protons

Mass number of aluminium  = 26.9

Therefore, Number of neutrons  = which is approximately equal to 14.

c. Beryllium ()

atomic number of beryllium is 4. Thus, number of protons = 4

And, number of electrons  = 4

Number of neutrons  = Mass number - Number of protons

Mass number of beryllium  = 9

Therefore, Number of neutrons  =

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

it takes on an electronical energy