Asolution is 0.0460 m nabr. what is the molarity of the solution if the density is 1.10 g/ml?

The molarity of NaBr = 0.05036M

0.0460 m  NaBr    has 0.0460 moles NaBr with 1000g of solvent

therefore the mass of NaBr= 0.0460 moles x 102.89 g/mol =4.73grams

total mass is therefore= 4.733 g +1000= 1004.73 grams

step 2:

use the density to determine the volume

vol=mass/density

=1004.73 g/1.10 g/mol=913.39 ml in liters= 913.39/1000=0.91339 L

now the molarity = moles/vol in liters

=0.0460 m/0.91339=0.05036  M

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