Na chemical reaction, substance r reacts with compound xy to produce 47.0 g of compound rx. if the theoretical yield of rx is 56.0 g, what is its percent yield? 9.00% 16.1% 83.9% 119%

The percent yield is 83.9 %.

% yield = actual yield/theoretical yield × 100 % = 47.0 g/56.0 g × 100 % = 83.9 %

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o