The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. how many grams would be produced from 7.70 g of butanoic acid and excess ethanol?

The mass of ester produced would be, 7.92 grams.

Explanation : Given,

Mass of butanoic acid = 7.70 g

Molar mass of butanoic acid = 88 g/mol

Molar mass of ethyl butyrate = 116 g/mol

First we have to calculate the moles of butanoic acid.

Now we have to calculate the moles of

The balanced chemical equation is:

From the balanced reaction we conclude that

As, 1 mole of react to give 1 mole of

So, 0.0875 mole of react to give 0.0875 mole of

Now we have to calculate the mass of

To calculate the amount of ester formed When the yield 78.0 % is calculated as follows:

Theoretical yield = 10.15 g

Now put all the given values in this formula, we get:

Therefore, the mass of ester produced would be, 7.92 grams.

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