The half-life of bismuth-210, 210bi, is 5 days. (a) if a sample has a mass of 160 mg, find the amount remaining after 15 days. mg

solution:

The general form of the equation would be A = P x  (1/2) ^ (t/h) where A = final amount, P = start amount, t = time (here in days) and h = half-life (has to be same units as t)  

a) A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg

the answer is:  

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